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I'm looking for a general method that works for all cubics, I really appreciate the help!Įdit: Okay, so I received a lot of feedback which explained why a ( x − j ) 3 + k would not work for all cubic equations because it only has one real root, and got pointers in the direction of depressed cubic equations. I have tried geometrically 'completing the cube' with a friend and found a way (?) to convert standard cubic expressions to their vertex form, but this method was only applicable to cubics without a linear term. The calculator returns the value of a and b for you to enter into the equation yax+b (in our equation, a -2.9 and b 15.06). Check the link below to see the steps on how to do an. However, I have not been able to find a method of converting a standard cubic function a x 3 + b x 2 + c x + d to its 'vertex form' as stated above that is applicable generally to all cubic functions. Exponential Regression Calculator - Statology Februby Zach Exponential Regression Calculator This calculator produces an exponential regression equation based on values for a predictor variable and a response variable. Enter the x -coordinates and y -coordinates in your calculator and do an exponential regression. Graphs a cubic function whose inflection point is (−j,k). My question is: can the same be done for cubic functions? Playing around with graphs have shown me that This is achieved by performing completing the square on the standard form of the quadratic function a x 2 + b x + c. Where (-p,q) represent the coordinates of the maximum or minimum point of the parabola. We're all familiar with the vertex form of a quadratic function, Converting a x 3 + b x 2 + c x + d to a ( x − j ) 3 + k
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